(-5:Bad argument) in function ‘rectangle’ – Can’t parse ‘pt1’. Sequence item with index 0 has a wrong type

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(-5:Bad argument) in function ‘rectangle’ – Can’t parse ‘pt1’. Sequence item with index 0 has a wrong type

  1. How to solve (-5:Bad argument) in function 'rectangle' – Can't parse 'pt1'. Sequence item with index 0 has a wrong type

    The problem is that you are passing tuples with floats into the function's parameters as the points. Here is the error reproduced:
    import cv2 import numpy as np img = np.zeros((600, 600), 'uint8') c1 = 50.2, 12.4 c2 = 88.8, 40.8 cv2.rectangle(img, c1, c2, (255, 0, 0), -1)
    Output:
    Traceback (most recent call last): File "C:/Users/User/Desktop/temp.py", line 9, in <module> cv2.rectangle(img, c1, c2, (255, 0, 0), -1) cv2.error: OpenCV(4.5.2) :-1: error: (-5:Bad argument) in function 'rectangle' > Overload resolution failed: > - Can't parse 'pt1'. Sequence item with index 0 has a wrong type > - Can't parse 'pt1'. Sequence item with index 0 has a wrong type > - Can't parse 'rec'. Expected sequence length 4, got 2 > - Can't parse 'rec'. Expected sequence length 4, got 2
    And to fix it, simply use the int() wrapper around the coordinates:
    import cv2 import numpy as np img = np.zeros((600, 600), 'uint8') c1 = 50.2, 12.4 c2 = 88.8, 40.8 cv2.rectangle(img, (int(c1[0]), int(c1[1])), (int(c2[0]), int(c2[1])), (255, 0, 0), -1)

  2. (-5:Bad argument) in function 'rectangle' – Can't parse 'pt1'. Sequence item with index 0 has a wrong type

    The problem is that you are passing tuples with floats into the function's parameters as the points. Here is the error reproduced:
    import cv2 import numpy as np img = np.zeros((600, 600), 'uint8') c1 = 50.2, 12.4 c2 = 88.8, 40.8 cv2.rectangle(img, c1, c2, (255, 0, 0), -1)
    Output:
    Traceback (most recent call last): File "C:/Users/User/Desktop/temp.py", line 9, in <module> cv2.rectangle(img, c1, c2, (255, 0, 0), -1) cv2.error: OpenCV(4.5.2) :-1: error: (-5:Bad argument) in function 'rectangle' > Overload resolution failed: > - Can't parse 'pt1'. Sequence item with index 0 has a wrong type > - Can't parse 'pt1'. Sequence item with index 0 has a wrong type > - Can't parse 'rec'. Expected sequence length 4, got 2 > - Can't parse 'rec'. Expected sequence length 4, got 2
    And to fix it, simply use the int() wrapper around the coordinates:
    import cv2 import numpy as np img = np.zeros((600, 600), 'uint8') c1 = 50.2, 12.4 c2 = 88.8, 40.8 cv2.rectangle(img, (int(c1[0]), int(c1[1])), (int(c2[0]), int(c2[1])), (255, 0, 0), -1)

Solution 1

The problem is that you are passing tuples with floats into the function’s parameters as the points. Here is the error reproduced:

import cv2
import numpy as np

img = np.zeros((600, 600), 'uint8')

c1 = 50.2, 12.4
c2 = 88.8, 40.8

cv2.rectangle(img, c1, c2, (255, 0, 0), -1)

Output:

Traceback (most recent call last):
  File "C:/Users/User/Desktop/temp.py", line 9, in <module>
    cv2.rectangle(img, c1, c2, (255, 0, 0), -1)
cv2.error: OpenCV(4.5.2) :-1: error: (-5:Bad argument) in function 'rectangle'
> Overload resolution failed:
>  - Can't parse 'pt1'. Sequence item with index 0 has a wrong type
>  - Can't parse 'pt1'. Sequence item with index 0 has a wrong type
>  - Can't parse 'rec'. Expected sequence length 4, got 2
>  - Can't parse 'rec'. Expected sequence length 4, got 2

And to fix it, simply use the int() wrapper around the coordinates:

import cv2
import numpy as np

img = np.zeros((600, 600), 'uint8')

c1 = 50.2, 12.4
c2 = 88.8, 40.8

cv2.rectangle(img, (int(c1[0]), int(c1[1])), (int(c2[0]), int(c2[1])), (255, 0, 0), -1)

Original Author Ann Zen Of This Content

Solution 2

Just try the below changes it’s works for me.

fontScale = 0.5
    score = out_scores[i]
    class_ind = int(out_classes[i])
    bbox_color = colors[class_ind]
    bbox_thick = int(0.6 * (image_h + image_w) / 600)
    c1, c2 = (coor[0], coor[1]), (coor[2], coor[3])
    print(c1, c2, bbox_color, bbox_thick)
    cv2.rectangle(image, (int(c1[0]), int(c1[1])), (int(c2[0]), int(c2[1])), bbox_color, bbox_thick)

    if show_label:
        bbox_mess = '%s: %.2f' % (classes[class_ind], score)
        t_size = cv2.getTextSize(bbox_mess, 0, fontScale, thickness=bbox_thick // 2)[0]
        c3 = (c1[0] + t_size[0], c1[1] - t_size[1] - 3)
        cv2.rectangle(image, (int(c1[0]), int(c1[1])), (int(c3[0]), int(c3[1])), (255, 0, 0), -1) #filled

        cv2.putText(image, bbox_mess, (int(c1[0]), int(c1[1] - 2)), cv2.FONT_HERSHEY_SIMPLEX,
                    fontScale, (0, 0, 0), bbox_thick // 2, lineType=cv2.LINE_AA)
return image

Original Author Darshana shah Of This Content

Solution 3

n_lines = len(bbox)
    for i in range(n_lines):
        # draw all lines
        point1 = tuple(bbox[i][0])
        point2 = tuple(bbox[(i+1) % n_lines][0])
        cv2.line(img, point1, point2, (255, 0, 0), thickness=2)

Original Author Varshini Of This Content

Conclusion

So This is all About This Tutorial. Hope This Tutorial Helped You. Thank You.

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I am an Information Technology Engineer. I have Completed my MCA And I have 4 Year Plus Experience, I am a web developer with knowledge of multiple back-end platforms Like PHP, Node.js, Python and frontend JavaScript frameworks Like Angular, React, and Vue.

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