# ArrayIndexOutOfBoundsException: Index 3 out of bounds for length 3

We Are Going To Discuss About ArrayIndexOutOfBoundsException: Index 3 out of bounds for length 3. So lets Start this Java Article.

## ArrayIndexOutOfBoundsException: Index 3 out of bounds for length 3

1. ArrayIndexOutOfBoundsException: Index 3 out of bounds for length 3

because array index start at 0
`public static void main(String[] args) { Scanner input = new Scanner(System.in); int n = 3; int[] numbers = new int[n]; float total = 0; for (int i = 0; i <= 2; i++) { int row=i+1;`

2. ArrayIndexOutOfBoundsException: Index 3 out of bounds for length 3

because array index start at 0
`public static void main(String[] args) { Scanner input = new Scanner(System.in); int n = 3; int[] numbers = new int[n]; float total = 0; for (int i = 0; i <= 2; i++) { int row=i+1;`

## Solution 1

because array index start at 0

`````` public static void main(String[] args) {

Scanner input = new Scanner(System.in);
int n = 3;
int[] numbers = new int[n];
float total = 0;

for (int i = 0; i <= 2; i++) {
int row=i+1;
System.out.println("Please type the number " + row + ":");
numbers[i] = input.nextInt();

total = total + numbers[i];

}

System.out.println("The average of the 3 number is: " + total / n);
}
``````

Original Author AMA Of This Content

## Solution 2

Indexes starts from 0. Your length is 3 and your counter variable (`i`) starts from 1.

You can use

``````for (int i = 0; i < 3; i++)
``````

Original Author Semih Çavdar Of This Content

## Solution 3

Try this, insert this inside your main method

``````Scanner input = new Scanner(System.in);

int n = 3;
int[] numbers = new int[n];
float total = 0;

for (int i = 0; i < 3; i++) {

System.out.println("Please type the number " + (i + 1) + ":");
numbers[i] = input.nextInt();

total = total + numbers[i];

}

System.out.println("The average of the 3 number is: " + total / n);
``````

Original Author Royeth Gomeseria Of This Content

## Solution 4

If you’re facing error listed below

Exception in thread “main” java.lang.ArrayIndexOutOfBoundsException: Index 3 out of bounds for length 3

``````var arr = arrayOf("One","Two","Three")
println(arr[3])
``````

In this Array we just defined three values and index start from 0, So Index 3 doesn’t exist in array that’s why it’s giving this Exception

Try to print index value which includes in Array Such As

``````println(arr[1])
``````

Original Author Rehan Khan Of This Content

## Conclusion

So This is all About This Tutorial. Hope This Tutorial Helped You. Thank You.