Create list of object from another using Java 8 Streams

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Create list of object from another using Java 8 Streams

  1. Create list of object from another using Java 8 Streams

    If you want to iterate over a list and create a new list with “transformed” objects, you should use the map() function of stream + collect(). In the following example I find all people with the last name “l1” and each person I'm “mapping” to a new Employee instance.

  2. Create list of object from another using Java 8 Streams

    If you want to iterate over a list and create a new list with “transformed” objects, you should use the map() function of stream + collect(). In the following example I find all people with the last name “l1” and each person I'm “mapping” to a new Employee instance.

Solution 1

If you want to iterate over a list and create a new list with “transformed” objects, you should use the map() function of stream + collect(). In the following example I find all people with the last name “l1” and each person I’m “mapping” to a new Employee instance.

public class Test {

    public static void main(String[] args) {
        List<Person> persons = Arrays.asList(
                new Person("e1", "l1"),
                new Person("e2", "l1"),
                new Person("e3", "l2"),
                new Person("e4", "l2")
        );

        List<Employee> employees = persons.stream()
                .filter(p -> p.getLastName().equals("l1"))
                .map(p -> new Employee(p.getName(), p.getLastName(), 1000))
                .collect(Collectors.toList());

        System.out.println(employees);
    }

}

class Person {

    private String name;
    private String lastName;

    public Person(String name, String lastName) {
        this.name = name;
        this.lastName = lastName;
    }

    // Getter & Setter
}

class Employee extends Person {

    private double salary;

    public Employee(String name, String lastName, double salary) {
        super(name, lastName);
        this.salary = salary;
    }

    // Getter & Setter
}

Original Author Rafael Teles Of This Content

Solution 2

What you are possibly looking for is map(). You can “convert” the objects in a stream to another by mapping this way:

...
 .map(userMeal -> new UserMealExceed(...))
...

Original Author Robert Bräutigam Of This Content

Solution 3

An addition to the solution by @Rafael Teles. The syntactic sugar Collectors.mapping does the same in one step:

//...
List<Employee> employees = persons.stream()
  .filter(p -> p.getLastName().equals("l1"))
  .collect(
    Collectors.mapping(
      p -> new Employee(p.getName(), p.getLastName(), 1000),
      Collectors.toList()));

Detailed example can be found here

Original Author Jónás Balázs Of This Content

Solution 4

I prefer to solve this in the classic way, creating a new array of my desired data type:

List<MyNewType> newArray = new ArrayList<>();
myOldArray.forEach(info -> newArray.add(objectMapper.convertValue(info, MyNewType.class)));

Original Author Henrique Schmitt Of This Content

Conclusion

So This is all About This Tutorial. Hope This Tutorial Helped You. Thank You.

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Siddharth

I am an Information Technology Engineer. I have Completed my MCA And I have 4 Year Plus Experience, I am a web developer with knowledge of multiple back-end platforms Like PHP, Node.js, Python and frontend JavaScript frameworks Like Angular, React, and Vue.

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