# Find the unique values in a column and then sort them

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## Find the unique values in a column and then sort them

How to solve Find the unique values in a column and then sort them

`sorted(iterable)`: Return a new sorted list from the items in iterable.
CODE
`import pandas as pd df = pd.DataFrame({'A':[1,1,3,2,6,2,8]}) a = df['A'].unique() print(sorted(a))`
OUTPUT
`[1, 2, 3, 6, 8]`

Find the unique values in a column and then sort them

`sorted(iterable)`: Return a new sorted list from the items in iterable.
CODE
`import pandas as pd df = pd.DataFrame({'A':[1,1,3,2,6,2,8]}) a = df['A'].unique() print(sorted(a))`
OUTPUT
`[1, 2, 3, 6, 8]`

## Solution 1

`sorted(iterable)`: Return a new sorted list from the items in iterable.

CODE

``````import pandas as pd
df = pd.DataFrame({'A':[1,1,3,2,6,2,8]})
a = df['A'].unique()
print(sorted(a))
``````

OUTPUT

``````[1, 2, 3, 6, 8]
``````

Original Author Vineet Kumar Doshi Of This Content

## Solution 2

`sort` sorts inplace so returns nothing:

``````In [54]:
df = pd.DataFrame({'A':[1,1,3,2,6,2,8]})
a = df['A'].unique()
a.sort()
a

Out[54]:
array([1, 2, 3, 6, 8], dtype=int64)
``````

So you have to call `print a` again after the call to `sort`.

Eg.:

``````In [55]:
df = pd.DataFrame({'A':[1,1,3,2,6,2,8]})
a = df['A'].unique()
a.sort()
print(a)

[1 2 3 6 8]
``````

Original Author EdChum Of This Content

## Solution 3

You can also use the drop_duplicates() instead of unique()

``````df = pd.DataFrame({'A':[1,1,3,2,6,2,8]})
a = df['A'].drop_duplicates()
a.sort()
print a
``````

Original Author Meloun Of This Content

## Solution 4

I prefer the oneliner:

``````print(sorted(df['Column Name'].unique()))
``````

Original Author MDMoore313 Of This Content

## Conclusion

So This is all About This Tutorial. Hope This Tutorial Helped You. Thank You.