We Are Going To Discuss About How to check for float(‘nan’) in Python?. So lets Start this Python Article.
How to check for float(‘nan’) in Python?
- How to solve How to check for float('nan') in Python?
It's very pedestrian, and a bit ugly, but why not just do the following?
import math import numpy as np if math.isnan(x) or x in ['nan', np.nan, ... ]: # Do something pass
I want to recommend a Yoda expression but haven't quite worked it out yet.
If you want to sweep everything under the carpet put it in a lambda or function.
Following on from https://stackoverflow.com/a/64090763/1021819, you can try to get the iterator to evaluate any in a lazy fashion. The problem then is that if none of the first conditions evaluates toTruethen themath.isnan()call is executed and can still throw theTypeError. If you evaluate lazily you can guard themath.isnan()call with a type check againststr:fn_list_to_check=[ lambda x: x in ['nan', np.nan, ... ], lambda x: not isinstance(x, str), lambda x: math.isnan(x) ] if any(f(x) for f in fn_list_to_check): # Do something pass
Note the absence of square list brackets in the any i.e.any()notany([])(who knew?).
I think it's quite brilliant but equally as ugly – choose your poison.
For the second part of the question (whyfloat('nan') != float('nan')), see
What is the rationale for all comparisons returning false for IEEE754 NaN values? - How to check for float('nan') in Python?
It's very pedestrian, and a bit ugly, but why not just do the following?
import math import numpy as np if math.isnan(x) or x in ['nan', np.nan, ... ]: # Do something pass
I want to recommend a Yoda expression but haven't quite worked it out yet.
If you want to sweep everything under the carpet put it in a lambda or function.
Following on from https://stackoverflow.com/a/64090763/1021819, you can try to get the iterator to evaluate any in a lazy fashion. The problem then is that if none of the first conditions evaluates toTruethen themath.isnan()call is executed and can still throw theTypeError. If you evaluate lazily you can guard themath.isnan()call with a type check againststr:fn_list_to_check=[ lambda x: x in ['nan', np.nan, ... ], lambda x: not isinstance(x, str), lambda x: math.isnan(x) ] if any(f(x) for f in fn_list_to_check): # Do something pass
Note the absence of square list brackets in the any i.e.any()notany([])(who knew?).
I think it's quite brilliant but equally as ugly – choose your poison.
For the second part of the question (whyfloat('nan') != float('nan')), see
What is the rationale for all comparisons returning false for IEEE754 NaN values?
Solution 1
It’s very pedestrian, and a bit ugly, but why not just do the following?
import math
import numpy as np
if math.isnan(x) or x in ['nan', np.nan, ... ]:
# Do something
pass
I want to recommend a Yoda expression but haven’t quite worked it out yet.
If you want to sweep everything under the carpet put it in a lambda or function.
Following on from https://stackoverflow.com/a/64090763/1021819, you can try to get the iterator to evaluate any in a lazy fashion. The problem then is that if none of the first conditions evaluates to True then the math.isnan() call is executed and can still throw the TypeError. If you evaluate lazily you can guard the math.isnan() call with a type check against str:
fn_list_to_check=[
lambda x: x in ['nan', np.nan, ... ],
lambda x: not isinstance(x, str),
lambda x: math.isnan(x)
]
if any(f(x) for f in fn_list_to_check):
# Do something
pass
Note the absence of square list brackets in the any i.e. any() not any([]) (who knew?).
I think it’s quite brilliant but equally as ugly – choose your poison.
For the second part of the question (why float('nan') != float('nan')), see
What is the rationale for all comparisons returning false for IEEE754 NaN values?
Original Author jtlz2 Of This Content
Solution 2
Why not just wrap whatever you pass to math.isnan with another float conversion? If it was already a float (i.e. float('nan')) you just made a “redundant” call:
import math
def is_nan(value):
return math.isnan(float(value))
And this seems to give your expected results:
>>> is_nan(float('nan'))
True
>>> is_nan('nan')
True
>>> is_nan(np.nan)
True
Original Author Tomerikoo Of This Content
Solution 3
You can check for NaN value like this,
def isNaN(num):
if num == 'nan':
return True
return num!= num
Original Author Gautam Jangid Of This Content
Conclusion
So This is all About This Tutorial. Hope This Tutorial Helped You. Thank You.
