We Are Going To Discuss About **How to replace values in numpy array at the same time **. So lets Start this Python Article.

## How to replace values in numpy array at the same time

**How to solve How to replace values in numpy array at the same time**It's better to use np.select if you've multiple conditions:

`a = np.array([7, 1, 2, 0, 2, 3, 4, 0, 5]) a = np.select([a == 7, a == 2], [2, 3], a)`

OUTPUT:`[2 1 3 0 3 3 4 0 5]`

**How to replace values in numpy array at the same time**It's better to use np.select if you've multiple conditions:

`a = np.array([7, 1, 2, 0, 2, 3, 4, 0, 5]) a = np.select([a == 7, a == 2], [2, 3], a)`

OUTPUT:`[2 1 3 0 3 3 4 0 5]`

## Solution 1

It’s better to use np.select if you’ve multiple conditions:

```
a = np.array([7, 1, 2, 0, 2, 3, 4, 0, 5])
a = np.select([a == 7, a == 2], [2, 3], a)
```

#### OUTPUT:

```
[2 1 3 0 3 3 4 0 5]
```

Original Author Nk03 Of This Content

## Solution 2

Numpy provide the comparison to a scalar with the standard `==`

operator, such that `arr == v`

return a boolean array. Taking `arr[arr == v]`

takes the subset (or slice) of `arr`

where the condition is met so this snippet should work.

```
import numpy as np
arr = np.array([7, 1, 2, 0, 2, 3, 4, 0, 5])
arr[arr == 7] = 2
arr
array([2, 1, 2, 0, 2, 3, 4, 0, 5])
```

Original Author Maxime A Of This Content

## Conclusion

So This is all About **This Tutorial.** Hope This Tutorial Helped You. Thank You.