We Are Going To Discuss About Python error – ImportError: attempted relative import with no known parent package . So lets Start this Python Article.
Python error – ImportError: attempted relative import with no known parent package
- How to solve Python error – ImportError: attempted relative import with no known parent package [duplicate]
Here is a reference that explains this problem well. Basically, the problem is that
__package__is not set when running standalone scripts.
File structure. └── project ├── server │ └── main.py └── utils └── module.py
project/server/main.pyif __name__ == '__main__': print(__package__)
Output$ python3 project/server/main.py None
As we can see, the value of__package__isNone. This is a problem because it is the basis of relative imports as stated here:__package__
… This attribute is used instead of__name__to calculate explicit relative imports for main modules, as defined in PEP 366…
Where PEP 366 explains this further:
The major proposed change is the introduction of a new module level attribute,__package__. When it is present, relative imports will be based on this attribute rather than the module__name__attribute.
To resolve this, you can run it as a module via -m flag instead of a standalone script.
Output$ python3 -m project.server.main # This can be <python3 -m project.server> if the file was named project/server/__main__.py project.server
project/server/main.pyfrom ..utils.module import my_function if __name__ == '__main__': print(__package__) print("Main") my_function()
Output$ python3 -m project.server.main project.server Main My function
Now,__package__is set, which means it can now resolve the explicit relative imports as documented above. - Python error – ImportError: attempted relative import with no known parent package [duplicate]
Here is a reference that explains this problem well. Basically, the problem is that
__package__is not set when running standalone scripts.
File structure. └── project ├── server │ └── main.py └── utils └── module.py
project/server/main.pyif __name__ == '__main__': print(__package__)
Output$ python3 project/server/main.py None
As we can see, the value of__package__isNone. This is a problem because it is the basis of relative imports as stated here:__package__
… This attribute is used instead of__name__to calculate explicit relative imports for main modules, as defined in PEP 366…
Where PEP 366 explains this further:
The major proposed change is the introduction of a new module level attribute,__package__. When it is present, relative imports will be based on this attribute rather than the module__name__attribute.
To resolve this, you can run it as a module via -m flag instead of a standalone script.
Output$ python3 -m project.server.main # This can be <python3 -m project.server> if the file was named project/server/__main__.py project.server
project/server/main.pyfrom ..utils.module import my_function if __name__ == '__main__': print(__package__) print("Main") my_function()
Output$ python3 -m project.server.main project.server Main My function
Now,__package__is set, which means it can now resolve the explicit relative imports as documented above.
Solution 1
Here is a reference that explains this problem well. Basically, the problem is that __package__ is not set when running standalone scripts.
File structure
.
└── project
├── server
│ └── main.py
└── utils
└── module.py
project/server/main.py
if __name__ == '__main__':
print(__package__)
Output
$ python3 project/server/main.py
None
As we can see, the value of __package__ is None. This is a problem because it is the basis of relative imports as stated here:
__package__… This attribute is used instead of
__name__to calculate explicit relative imports for main modules, as defined in PEP 366…
Where PEP 366 explains this further:
The major proposed change is the introduction of a new module level attribute,
__package__. When it is present, relative imports will be based on this attribute rather than the module__name__attribute.
To resolve this, you can run it as a module via -m flag instead of a standalone script.
Output
$ python3 -m project.server.main # This can be <python3 -m project.server> if the file was named project/server/__main__.py
project.server
project/server/main.py
from ..utils.module import my_function
if __name__ == '__main__':
print(__package__)
print("Main")
my_function()
Output
$ python3 -m project.server.main
project.server
Main
My function
Now, __package__ is set, which means it can now resolve the explicit relative imports as documented above.
Original Author Niel Godfrey Ponciano Of This Content
Solution 2
You can try without using from ..util.module import my_function rather try direct import my_function.
If it doesn’t work you need to create a new file which can be empty named as __init__.py under both utils folder and server folder. __init__.py creates an actual module that can be called for any module.
Hope it works.
Original Author Fatin Ishrak Rafi Of This Content
Conclusion
So This is all About This Tutorial. Hope This Tutorial Helped You. Thank You.
